我靠这个还要构造解。。。。
WA ing
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 | const int N = 1000, M = N*N; VI in[N], out[N]; struct Simplex { const static int N = int (1e4) + 9, M = int (1e4) + 9; DB a[N][M]; int b[N], c[M], X[M]; int n, m; void pivot( int in, int out) { REP(i, m+1) if (i!=in) a[out][i] /= -a[out][in]; //重置out约束 a[out][in] = 1/a[out][in]; REP(i, n+1) if (i!=out && sgn(a[i][in])) { //重新计算其他约束 DB t = a[i][in]; a[i][in] = 0; REP(j, m+1) a[i][j] += t*a[out][j]; } swap(c[in], b[out]); } void run() { REP_1(i, n) b[i] = -i; REP_1(i, m) c[i] = i; while ( true ) { int in=0, out=0; DB Min=OO; REP_1(i, m) if (sgn(a[0][i])>0) { in=i; break ; } if (!in) return ; REP_1(i, n) if (sgn(a[i][in])<0&&a[i][0]/-a[i][in]<Min) { Min=a[i][0]/-a[i][in]; out=i; } if (!out) return ; //throw ; //unbounded pivot(in, out); } } struct Edge { int x,y,w,s,t; void in() { RD(x,y,w,s,t); --x; --y; } } E[::M]; void gao() { // z c // b A RD(n, m); REP(i, n) { in[i].clear(); out[i].clear(); } REP(i, m){ E[i].in(); int x = E[i].x, y = E[i].y, w = E[i].w, s = E[i].s, t = E[i].t; in[x].PB(y); out[y].PB(x); a[0][0] += w; DB (&r0)[M] = a[i+1]; r0[0] = t - w; r0[x+1] -= 1; r0[n+y+1] += 1; DB (&r1)[M] = a[m+i+1]; r1[0] = w - s; r1[x+1] += 1; r1[n+y+1] -= 1; } REP(i, n) a[0][i+1] += SZ(out[i]); REP(i, n) a[0][n+i+1] -= SZ(in[i]); n *= 2; m *= 2; swap(n, m); /* REP(i, n+1) { REP(j, m+1) cout << a[i][j] << " "; cout << endl; } REP_1(i, n) cout << b[i] << " "; cout << endl; REP_1(i, m) cout << c[i] << " "; cout << endl; REP_1(i, m) cout << X[i] << " "; cout << endl; */ run(); /* cout << "-----------" << endl; REP(i, n+1) { REP(j, m+1) cout << a[i][j] << " "; cout << endl; } cout << "-----------" << endl; */ /*REP_1(i, m/2) { cout << a[0][i] << " "<< a[0][m/2+i] << endl; }*/ REP_1(i, m) X[i] = 0; REP_1(i, n) if (b[i] > 0) X[b[i]] = a[i][0]; /* REP_1(i, n) cout << b[i] << " "; cout << endl; REP_1(i, m) cout << c[i] << " "; cout << endl; REP_1(i, m) cout << X[i] << " "; cout << endl; */ REP(i, n/2) { int x = E[i].x, y = E[i].y, w = E[i].w, s = E[i].s, t = E[i].t; w += X[x+1]; w -= X[m/2+y+1]; if (w < s || t < w) { puts ( "Unlike" ); REP(i, n+1) { REP(j, m+1) a[i][j] = 0; } return ; } } OT((LL)a[0][0]); REP_1(i, m/2) { cout << (LL)X[i] << " " << (LL)X[m/2+i] << endl; } REP(i, n+1) { REP(j, m+1) a[i][j] = 0; } } } fst; int main() { #ifndef ONLINE_JUDGE freopen ( "in.txt" , "r" , stdin); //freopen("out.txt", "w", stdout); #endif Rush fst.gao(); } |